Step of Proof: ax_choice |
12,41 |
|
Inference at * 1 1 1
Iof proof for Lemma ax choice:
1. A : Type
2. B : Type
3. Q : A
B

4. g : x:A
y:B
Q(x,y)
5. x : A
Q(x,(g(x)).1)
by ((With x (D 4))
CollapseTHENA ((Auto_aux (first_nat 1:n) ((first_nat 1:n),(first_nat 4:n
C)) (first_tok :t) inil_term)))
C1:
C1: 6. y : y:B
Q(x,y)
C1: 7. y = g(x)
C1:
Q(x,(g(x)).1)
C.